嵌入式开发者社区
标题:
TL138 uboot是怎么区分配置两款核心板的
[打印本页]
作者:
Mr.Loser
时间:
2014-9-11 09:33
标题:
TL138 uboot是怎么区分配置两款核心板的
核心板1:DDR2 128M Byte NAND FLASH 4G bit
, h2 F0 C. x7 p7 g
核心板2:DDR2 256M Byte NAND FLASH 8G bit
. z% h, ~3 ], K8 y+ }
这两个核心板公共一个uboot,DDR2的配置肯定是不同的,uboot怎么检查到是哪个核心板,然后去执行相应的配置呢?
, X3 F- z% D. {- \3 N
5 M9 p/ T( {6 P
是不是通过读NAND FLASH的ID,两款核心板NAND FLASH不同,ID也不同,这样读到了ID就知道是哪个核心板了?
* Y: ~& g5 M) ^- O" a* {/ g4 ^% T, h
e6 Y% _) {! x( @! t
作者:
2532609929
时间:
2014-9-11 18:55
DDR通过检查最大有效地址来识别容量,具体请看uboot的common/memsize.c文件中的检查代码,也可以看如下:
3 u# @( w F- s4 l* d8 b
/*
5 u2 K5 `- S- M8 D
* Check memory range for valid RAM. A simple memory test determines
- u9 E( ^9 V! T9 F9 o y- N
* the actually available RAM size between addresses `base' and
% B7 X# t$ J' _& u& F& ?& c
* `base + maxsize'.
: q T% l& U$ A$ O+ b1 N
*/
4 Q8 X# v F3 D- [- I
long get_ram_size(long *base, long maxsize)
+ D. Y) ~1 g! A f( g) l t' p+ i
{
' s$ ?+ K1 \# w; `" `9 F
volatile long *addr;
. v. N" l4 l) |6 f9 J
long save[32];
/ [3 f' {" l' A; Q. n3 F
long cnt;
' U# m# n1 A6 m/ \( G& O; l
long val;
/ F/ w1 _' U: l/ k
long size;
, A/ ~* A o* [, A: @1 x9 `: e
int i = 0;
8 V* Q; J0 f! T/ X
; e0 s8 I! B4 L# A
for (cnt = (maxsize / sizeof (long)) >> 1; cnt > 0; cnt >>= 1) {
! d$ J+ F1 A2 E6 [, e
addr = base + cnt; /* pointer arith! */
# H. Z; `+ h0 h' m0 U+ e- u2 M
sync ();
c7 {+ Z! g# `
save[i++] = *addr;
$ x, g$ y9 K1 m) ^* [* M5 `) W# O6 T
sync ();
6 x* }) w1 v3 O: l4 N! `
*addr = ~cnt;
' y7 [3 w! @/ n. l b# v
}
9 k! q* q# t" \$ Q8 ~0 h! H4 Y
" d2 @1 {4 g3 N) [1 u; L4 c
addr = base;
! @5 i3 L1 i2 c& W; Q' b
sync ();
8 y$ S/ B d3 { K- `* m
save
= *addr;
/ d: A5 T N% S0 H, F6 \6 M+ o
sync ();
* Y9 _- r% Z0 R& S8 z8 s& z0 A/ G
*addr = 0;
7 @7 r) F( X4 C
Y, n: ~; h* Z; l! H
sync ();
& ?# @3 [9 n3 h% L7 \& Q, E
if ((val = *addr) != 0) {
$ d. P6 M2 k/ t
/* Restore the original data before leaving the function.
* v) v+ L+ w6 t h
*/
. a+ F8 U7 K) h5 K0 N( u2 E0 `
sync ();
1 N% G; }5 j" I! b( b
*addr = save
;
7 b1 @0 l$ R" a, U) m- Y) q
for (cnt = 1; cnt < maxsize / sizeof(long); cnt <<= 1) {
4 H, G- N* n3 W0 q3 F+ G0 ~5 |
addr = base + cnt;
1 K4 {- o* v$ Z* t2 ?
sync ();
2 E6 ^$ F/ t( ~4 P& _5 f9 v2 j
*addr = save[--i];
% T& K. w+ F( s; z- |2 L
}
4 Z: S0 M, C( y+ T0 |3 f3 t' k
return (0);
7 r5 @1 A7 J8 m' g% t8 m
}
$ G' @ n2 P# T/ ]' o
! `5 L- f6 S8 w2 `
for (cnt = 1; cnt < maxsize / sizeof (long); cnt <<= 1) {
8 v# E, ^4 l! [8 k+ ]
addr = base + cnt; /* pointer arith! */
/ s% d! k. h$ N, b# V7 Z: {; s- v
val = *addr;
7 T( k5 \4 d0 k0 i1 c6 U/ x- n
*addr = save[--i];
]& u! z8 u4 W: H9 [. Y4 w' C( Q
if (val != ~cnt) {
3 I: I* o8 b& x2 F5 a! ^. b
size = cnt * sizeof (long);
/ w& f/ t! V1 J- \+ }
/* Restore the original data before leaving the function.
- b& h4 K* O, v/ C9 d; Y0 @) j
*/
: D0 N) P0 I1 ~ e
for (cnt <<= 1; cnt < maxsize / sizeof (long); cnt <<= 1) {
. \8 w2 O3 R$ W K# I
addr = base + cnt;
4 g% l- ~" ~% ?9 s$ B
*addr = save[--i];
1 o: T; R8 |9 W' t6 W# K) `
}
! [2 I6 j2 D) u; l0 {: d) A
return (size);
. H, ?7 Y; E) N( d# C2 u/ U
}
& L2 S- o' _: ]! r9 S2 ?) J
}
, o# L1 _" z c B+ T# z
4 G% `$ |3 H" ~0 e! Y9 I8 r# R( B
return (maxsize);
( W& Q2 _% r+ g J
}
% T5 r! e! b9 x( Z' a# n
int dram_init(void)
/ `; q: G+ k. ]3 ?: O7 \) K
{
9 Z# H" O8 Y$ B+ j
/* dram_init must store complete ramsize in gd->ram_size */
- C6 o1 F {9 L# Q
gd->ram_size = get_ram_size(
' w. M, w$ y& s+ W
(void *)CONFIG_SYS_SDRAM_BASE,
; Q; d& t$ R+ ?
CONFIG_MAX_RAM_BANK_SIZE);
$ A' H3 Q0 j' N
return 0;
6 D- U5 l# g5 p0 [$ T, R2 a" X
}
# ?- x6 t" {6 a' [
& S2 i# C6 z# m, s
% V; R! l/ e* l% L$ b) i
% T# j# p1 O( L! ]) P
% Z& ~: C7 ?2 p/ i' K
FLASH是通过检查FLASH内部的ID识别容量,希望对您有帮助!
9 R, ?- z9 N# t; g _9 V' B$ I
; L) p/ T* k, N
_7 |$ ]- F5 V' I" {2 ?8 |
1 T! \8 d/ S$ Q$ h# P
欢迎光临 嵌入式开发者社区 (https://www.51ele.net/)
Powered by Discuz! X3.4