嵌入式开发者社区
标题:
TL138 uboot是怎么区分配置两款核心板的
[打印本页]
作者:
Mr.Loser
时间:
2014-9-11 09:33
标题:
TL138 uboot是怎么区分配置两款核心板的
核心板1:DDR2 128M Byte NAND FLASH 4G bit
6 H# N0 g1 ]% I4 ~) W( Y4 J! a
核心板2:DDR2 256M Byte NAND FLASH 8G bit
# n$ u0 D3 M% B2 b1 d
这两个核心板公共一个uboot,DDR2的配置肯定是不同的,uboot怎么检查到是哪个核心板,然后去执行相应的配置呢?
1 b* M, F8 g |
b8 R; y% E2 w# b4 p) a2 {" A
是不是通过读NAND FLASH的ID,两款核心板NAND FLASH不同,ID也不同,这样读到了ID就知道是哪个核心板了?
+ Y+ @+ c; j* w* A" G
& J$ k$ n( _. K: q/ L- `6 ?/ i
作者:
2532609929
时间:
2014-9-11 18:55
DDR通过检查最大有效地址来识别容量,具体请看uboot的common/memsize.c文件中的检查代码,也可以看如下:
8 `# t$ S2 M0 _+ M' e
/*
! {: z& k! i# O* ~& c$ Q
* Check memory range for valid RAM. A simple memory test determines
6 s2 T B9 [5 k
* the actually available RAM size between addresses `base' and
, p' n6 [/ `3 k
* `base + maxsize'.
6 Z# v& D- _# w) l6 o; W
*/
1 }$ [( A( ]* c" U8 H
long get_ram_size(long *base, long maxsize)
- I- K& p" b* A
{
$ P1 \# f7 n ?" e& s
volatile long *addr;
# T1 K; W4 A7 ?1 z5 I
long save[32];
. f' d9 d: ?/ M+ u6 P& _. `/ z
long cnt;
! y J7 {( e& M1 E' |+ s4 ^ `
long val;
* `( W! I3 O9 B2 \3 q" |/ F3 h
long size;
- w5 a- w. G% U* F Y# ?$ Q2 o- J
int i = 0;
2 h2 s/ p# P" p* G) j
5 r" _' ?+ |& U" G5 y7 E4 l9 r
for (cnt = (maxsize / sizeof (long)) >> 1; cnt > 0; cnt >>= 1) {
) I# D9 V) l2 H& A2 V
addr = base + cnt; /* pointer arith! */
6 h1 H( y1 V1 S$ ] z4 T, G
sync ();
' }$ F4 x% @6 [- S7 ~1 g( V( M c
save[i++] = *addr;
/ @! r1 ^+ e& n; R8 _" Q, i
sync ();
) _: k9 ^( G' r5 l$ ^
*addr = ~cnt;
" c% c2 r- p- _8 g( w$ i' @
}
( l4 c2 f/ A( G6 z" X
' W& d z% f2 F
addr = base;
( w% |/ M( Z0 G# k9 a
sync ();
; y6 {: M1 n( |7 V! R5 ]8 O, c
save
= *addr;
! D) U& t D/ V; q
sync ();
- K) d5 b1 L, n: y5 J' y
*addr = 0;
- o2 w7 M7 ?7 i
5 b4 u d8 L/ k, b+ i
sync ();
H0 c) M5 a J3 W4 K4 t( j
if ((val = *addr) != 0) {
* w" w# H- Y& l+ h" r) t
/* Restore the original data before leaving the function.
}* H/ j8 a+ B9 G2 d+ i% A
*/
( }: }( F% Y5 f& |
sync ();
8 o* b9 e5 g1 l2 F* I
*addr = save
;
6 I$ D' ?7 |- T. ]1 ?
for (cnt = 1; cnt < maxsize / sizeof(long); cnt <<= 1) {
- O7 s' \. } U3 ^$ Q
addr = base + cnt;
" J9 ^- r1 z' Y7 Q
sync ();
0 H( D" ?% b& d* V3 |, |
*addr = save[--i];
5 p2 `3 K( Z% C7 S& ?: L8 a
}
5 [8 x! G1 a( K7 ?& ~+ _4 {
return (0);
4 c+ j4 \( S% ?. n
}
5 s3 ^$ c/ e/ S# A U$ L
+ o* S" W& ? a
for (cnt = 1; cnt < maxsize / sizeof (long); cnt <<= 1) {
) N) n# I% c) I) _- Z5 A2 @% x
addr = base + cnt; /* pointer arith! */
, e- U, x6 b! T- z, q( f* k
val = *addr;
+ c, f3 b, a: s" |9 z2 K* C
*addr = save[--i];
8 z% B+ h4 z/ G4 t) A" v8 _ v
if (val != ~cnt) {
; s4 ^! {" R5 c+ ~7 w
size = cnt * sizeof (long);
( g! w6 ]& T& C5 ^
/* Restore the original data before leaving the function.
. h, J# Z( ~2 `9 l' ]6 {/ I
*/
9 ]* {1 l* h- r
for (cnt <<= 1; cnt < maxsize / sizeof (long); cnt <<= 1) {
F p9 v, i2 D& n- G6 x
addr = base + cnt;
$ k0 i* Q0 i8 X* g( `
*addr = save[--i];
8 V3 h' ^9 T5 R7 G: H8 D( J
}
& g; Z- z& z9 ^: C- u" b9 n
return (size);
1 W/ C8 a# V" Y: ]4 m$ S% j
}
7 ?4 F! J0 g, N
}
7 ]$ _* z c7 A: w
0 ^- a; @; `5 k, I# m+ |9 Q- B
return (maxsize);
6 |2 r, W8 L" D
}
6 S- G" E% p6 e4 ^% K+ @: ^
int dram_init(void)
% k+ O4 p3 z3 u* Z7 ^; W, H
{
! J. e/ h7 N" c. _7 {3 g
/* dram_init must store complete ramsize in gd->ram_size */
1 V4 Z( ~! q7 a, }8 R
gd->ram_size = get_ram_size(
( d1 m9 y% N; D4 \' D
(void *)CONFIG_SYS_SDRAM_BASE,
/ A* t% v( X2 x0 |2 [. z- h
CONFIG_MAX_RAM_BANK_SIZE);
5 x) I% n9 q" l
return 0;
7 D c! c/ |# N% @
}
t! `; g0 A8 ^: b" Y: p
! Y9 @& ^' u4 F1 k1 m
' R6 \& ?. `, Y- b7 t
9 _7 T1 Z. S. i% d# g
: ]' l, z4 H. T- g5 _! b
FLASH是通过检查FLASH内部的ID识别容量,希望对您有帮助!
% [. |0 X5 e x5 p! R1 H! M
# g& s K9 L- K! D
: f, K# q! a0 x$ F' f3 @0 I# Y7 ]( a
* g/ b }3 w' C; i& [/ k6 M
欢迎光临 嵌入式开发者社区 (https://www.51ele.net/)
Powered by Discuz! X3.4