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下面的任务,只能在第一次执行UPP时成功,后面的均不成功,请创龙工程师看看为什么?! I) a8 k6 K$ q$ n* J5 z
Void UPP_TASK(Void)- Y" j* I: w J" l. S: R
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2 i1 x. t. s% C, ^& o: K8 Z5 R int i,j,k,target_int_count=2;
; l$ z# J2 i6 Z" V* a5 n* A char ch[2];/ V5 f, l# B: R! p7 q
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0 l" W9 a& h, v! ~ upp_interrupt_count = 0;5 d1 H0 l9 m, `# a4 ?+ A" i" l0 p
upp_error_count = 0;9 k Q' e" y& Q; E3 X8 y6 x7 J8 z
6 c; V% T: F+ v. l% w UARTPuts("\tResetting uPP buffers...\r\n",-2);; d2 F. ], L. ?+ k
// Initialize data buffers
5 t5 X! r/ U8 Z, ?6 d+ Q: X for (i = 0; i < upp_frame_size; i++)0 I- B7 ~# \, k) m: d
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upp_buffer_b =i;
( @& Y, r6 C6 g) M8 n upp_buffer_a = 0xDEAD;; n9 _, A# n6 ^5 I8 ~$ x( O( K
}
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//for(i=0;i<1024;i++)9 g6 R( y: q2 i' f c, J/ z, S
// temp=0;4 T- B3 p* j/ z, D0 [# F Q C; d
7 `7 {2 X& B% A4 B* o { //UPPReset();& k1 [$ I6 U& o5 D5 A
/*启动UPP DMA传输*/
: u% e" z' s+ c' r* I+ { UARTPuts("upp_prog_dma_i\n",-2);! c6 k- A, E6 x1 e% u9 k% T8 Q
upp_reg_hdl->UPID0 = (Uint32)upp_buffer_a;6 }0 }) U+ `- v7 A. d
upp_reg_hdl->UPID1 = ((Uint32)upp_line_count << 16) | (Uint32)upp_line_size*sizeof(Int16);
0 f- H- `' d- P upp_reg_hdl->UPID2 = (Uint32)upp_line_offset*sizeof(Int16);' ?4 `9 N T4 t3 B8 ?) Y0 _: |! C
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UARTPuts("upp_prog_dma_i\n",-2);6 `: @* d; y+ w2 i
upp_reg_hdl->UPQD0 = (Uint32)upp_buffer_b;- \% U% f* y. l6 ^: Y
upp_reg_hdl->UPQD1 = ((Uint32)upp_line_count << 16) | (Uint32)upp_line_size*sizeof(Int16);3 M" u/ l& ^+ W9 a- P
upp_reg_hdl->UPQD2 = (Uint32)upp_line_offset*sizeof(Int16);- K9 e3 i$ y2 r* S3 H7 j
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/*等待UPP传输完毕*// l d! d5 X* o# E3 t1 f/ h3 c
//i=0;
2 `4 E0 b8 P. z3 c3 P //j=0;! s, D2 @( k$ Q8 Q; H% E; h! n( |
while (upp_interrupt_count < target_int_count && upp_error_count == 0)( J% N" _- _& `6 U
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/* 测试UPP传输的同时操作普通DDR数据
; u4 B/ Q1 W8 P& \7 Y& v temp=i;
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if(i==1024)0 U' Q+ L+ u2 ~' [1 _9 t# b
{
2 u7 \, ^; ?& c$ j i=0;. U2 A, X* Q& u) I: H2 W
j++;
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; b4 ]' t) A5 x: r */
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asm(" nop");
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//UARTprintf( "upp_interrupt_count=%d\n",upp_interrupt_count);/ L' s* ?5 M. Q! Y
}
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/*检查UPP传输的数据是否正确 (loopback modes only)*/
4 s1 r( w' H7 c5 p1 o8 ]2 i //UARTprintf( "i=%d\n",i);
6 T5 } q" y; P w9 i. Y( O% w //UARTprintf( "j=%d\n",j);
8 M% W5 R* K. K* Y7 E6 Z' G5 v UARTPuts("Data mismatch in buffers.\n",-2);
# R( B8 @& ]2 N4 b$ P if (upp_interrupt_count == 2 && upp_error_count == 0)
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8 j6 B$ Q/ {& C3 J7 Q for (i = 0; i<upp_frame_size; i++)- ^2 H0 B- p$ k
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if (upp_buffer_a != upp_buffer_b)# ?3 @( @8 A- h5 j9 ]
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upp_error_count++;
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}
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( ~' B0 n! C6 n /* 报告通信结果*/; i. E1 f5 X& o5 u& T
if(upp_error_count != 0)
+ T5 }% x- d/ ]0 {- t% c UARTprintf( "upp_error_count=%d\n",upp_error_count);
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0 Z4 _2 _+ v) V l2 v& E$ }! s UARTPuts("uPP transfers complete!\n",-2);
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UARTPuts("Do you want to print all the data?(y/n) ",-2);
) `# K+ P0 ]1 x. I* V6 O) h UARTGets(ch,2);
; B' L7 N) W1 p. l( C; ] UARTPuts("\n", -2);& m* i3 |/ B, S+ R
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if(ch[0] == 'y')
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/*打印全部读到的数据*/3 i. M3 b# k/ ?" {, T# Q, T7 C! m
for(i=0; i<upp_frame_size; )
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for(j=0; j<5; j++)
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8 E5 G9 p% n6 N& x UARTprintf("upp_buffer_a[%d]=%d ",i,upp_buffer_a);9 W$ ?. D3 x' w2 i& X' x8 n( V6 G; V5 l
i++;
* x2 W4 J( D8 V1 v. J; C //if(i >= 4096)( l6 W; m7 Q. f/ X
// break;
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UARTPuts("\n",-2);7 D. h. k. @# A5 V. B9 y) [% g2 |" J
}
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}
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